Bill Cristall - Height Weight Birthday Zodiac Biography

Bill Cristall’s height is 5ft 7in (1.70 m)

William Arthur “Bill” Cristall (September 12, 1875 – January 28, 1939) was a Major League Baseball pitcher who played with the Cleveland Indians in 1901. Cristall batted and threw left-handed. His playing height and weight were listed as 5 foot 7 inches and 145 lbs.

First Name: William
Middle Name: Arthur
Last Name: Cristall
Birth Full Name: William Arthur Cristall
Other Names: Lefty
Born: 12 September, 1875
Birthplace: Odessa, Russia
Died: 28 January, 1939
Death Location: Buffalo, NY
Height: 5ft 7in (1.70 m)
Weight: 145 lbs (65.8 kg)
Astrological Sign: Virgo
Nationality: Russian
Occupation: Former Major League Baseball Player

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