Anastasiya Yakimova - Height Weight Birthday Zodiac Biography

Anastasiya Yakimova’s height is 5ft 5in (1.65 m)

Anastasiya Yakimova (Belarusian: Настасся Аляксееўна Якімава; Анастасия Алексеевна Екимова; born 1 November 1986) is a tennis player from Belarus. She made it to the third round of the 2007 Australian Open, defeating Ai Sugiyama of Japan, a seeded player, on the way in the second round.

First Name: Anastasiya
Last Name: Yakimova
Born: 1 November, 1986
Birthplace: Minsk, Soviet Union
Height: 5ft 5in (1.65 m)
Weight: 120 lbs (54.4 kg)
Astrological Sign: Scorpio
Nationality: Belarusian

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